有一个群友在群里问个如何快速搭建一个搜索引擎，在搜索之后我看到了这个
代码所在
- Git:https://github.com/asciimoo/searx
官方很贴心，很方便的是已经提供了docker 镜像，基本pull下来就可以很方便的使用了，执行命令
- cid=$(sudo docker ps -a | grep searx | awk '{print $1}')
- echo searx cid is $cid
- if [ "$cid" != "" ];then
- sudo docker stop $cid
- sudo docker rm $cid
- fi
- sudo docker run -d --name searx -e IMAGE_PROXY=True -e BASE_URL=http://yourdomain.com -p 7777:8888 wonderfall/searx
然后就可以使用了,正常查看docker的状态，就可以正常的使用了
思考
怎么样，是不是很方便，我们先看看源码是怎么样实现的
我们打开里面的代码，其实本质就是将request之后的结果做一个大的聚合，至于数据来源，我们可以是来于DB,或者文件，我们可以看一下他的核心代码
- from urllib import urlencode
- from json import loads
- from collections import Iterable
- search_url = None
- url_query = None
- content_query = None
- title_query = None
- suggestion_query = ''
- results_query = ''
- # parameters for engines with paging support
- #
- # number of results on each page
- # (only needed if the site requires not a page number, but an offset)
- page_size = 1
- # number of the first page (usually 0 or 1)
- first_page_num = 1
- def iterate(iterable):
- if type(iterable) == dict:
- it = iterable.iteritems()
- else:
- it = enumerate(iterable)
- for index, value in it:
- yield str(index), value
- def is_iterable(obj):
- if type(obj) == str:
- return False
- if type(obj) == unicode:
- return False
- return isinstance(obj, Iterable)
- def parse(query):
- q = []
- for part in query.split('/'):
- if part == '':
- continue
- else:
- q.append(part)
- return q
- def do_query(data, q):
- ret = []
- if not q:
- return ret
- qqkey = q[0]
- for key, value in iterate(data):
- if len(q) == 1:
- if key == qkey:
- ret.append(value)
- elif is_iterable(value):
- ret.extend(do_query(value, q))
- else:
- if not is_iterable(value):
- continue
- if key == qkey:
- ret.extend(do_query(value, q[1:]))
- else:
- ret.extend(do_query(value, q))
- return ret
- def query(data, query_string):
- q = parse(query_string)
- return do_query(data, q)
- def request(query, params):
- query = urlencode({'q': query})[2:]
- fp = {'query': query}
- if paging and search_url.find('{pageno}') >= 0:
- fp['pageno'] = (params['pageno'] - 1) * page_size + first_page_num
- params['url'] = search_url.format(**fp)
- params['query'] = query
- return params
- def response(resp):
- results = []
- json = loads(resp.text)
- if results_query:
- for result in query(json, results_query)[0]:
- url = query(result, url_query)[0]
- title = query(result, title_query)[0]
- content = query(result, content_query)[0]
- results.append({'url': url, 'title': title, 'content': content})
- else:
- for url, title, content in zip(
- query(json, url_query),
- query(json, title_query),
- query(json, content_query)
- ):
- results.append({'url': url, 'title': title, 'content': content})
- if not suggestion_query:
- return results
- for suggestion in query(json, suggestion_query):
- results.append({'suggestion': suggestion})
- return results
结果
每个response的时候我们都要以轻松的定制返回的数据（可以是网络，可以是数据库，可以是文件），那我们进一步想一下，如果我们可以hack response 结果，那我们完全可以将自己爬来的数据做为返回结果。如果是1024之类的，完全可以打造自己的“爱好”小引擎，代码我就不贴了，大家可以自己动手自己玩玩。结合jieba分词，可以更好玩一点。
